throwback Maths 13

throwback 13
Solution

Fromt solution diagram, we can see that the right angle in the square is composed of two angles, $\frac{360}{7}$ and $90-\frac{360}{7}$. It follows that

$$\theta = 180^\circ - \left(90 - \frac{360}{7}\right)  = 90 + \frac{360}{7} = 141\frac{3}{7}$$

sol image