throwback maths 2

A question of composite areas!

throwback 2
Solution

The shape is composed of a rectangle and a triangle. The rectangle has dimensions of $3cm \times 8cm$ and so has an area of $3\times 8 = 24cm^2$. The triangle is $3cm$ wide and $4cm$ tall. The area of the triangle is therefore $\frac{1}{2}\times 3 \times 4 = 6cm^2$

The total area of the shape is $24 + 6 = 30cm^2$